Respuesta :
let
x-------> the density of oak wood
y------> the density of sugar maple wood
we know that
x=0.75 g/cm³-----> equation 1
x=0.41+(y/2)-----> equation 2
substitute the equation 1 in equation 2
0.75=0.41+y/2-----> multiply by 2 both sides---> 1.5=0.82+y
y=1.5-0.82----> y=0.68 g/cm³
the answer is
the density of sugar maple wood is 0.68 g/cm³
x-------> the density of oak wood
y------> the density of sugar maple wood
we know that
x=0.75 g/cm³-----> equation 1
x=0.41+(y/2)-----> equation 2
substitute the equation 1 in equation 2
0.75=0.41+y/2-----> multiply by 2 both sides---> 1.5=0.82+y
y=1.5-0.82----> y=0.68 g/cm³
the answer is
the density of sugar maple wood is 0.68 g/cm³
There are 3 parts to this problem:
1- let x be=the density of the sugar maple wood
2- the equation is .75=.5x+.41
3- the density of the sugar maple wood is .68.
Don't worry, I just did this problem so this would be correct. :)
1- let x be=the density of the sugar maple wood
2- the equation is .75=.5x+.41
3- the density of the sugar maple wood is .68.
Don't worry, I just did this problem so this would be correct. :)