A truck heading east has an initial velocity of 6 m/s. It accelerates at 2 m/s2 for 12 seconds. What distance does the truck travel in the given time?

-- The truck begins the scenario moving at 6 m/s.

-- After increasing its speed at the rate of 2 m/s² for 12 seconds,
it has gained (2 x 12) = 24 m/s of speed, and it's then moving
at 30 m/s.

-- The truck's average speed during the 12 seconds is (1/2) (6 + 30) = 18 m/s

-- Traveling at an average speed of 18 m/s for 12 seconds,
the truck travels

(18 m/s) x (12 sec) = 216 meters

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rahulsharma789888 rahulsharma789888 · Answer 2 · 2022-08-10T14:36:05+02:00

A truck heading east has an initial velocity of 6 m/s. It accelerates at 2 m/s2 for 12 seconds. then the distance traveled by truck in the given time would be 30 meters

What are the three equations of motion?

There are three equations of motion given by Newton

The first equation is given as follows

v = u + at

the second equation is given as follows

S = ut + 1/2×a×t²

the third equation is given as follows

v² - u² = 2×a×s

As given in the problem a truck heading east has an initial velocity of 6 m/s. It accelerates at 2 m/s² for 12 seconds

By using the second equation of the motion and substituting the respective values of the initial velocity and the acceleration

S = ut + 1/2*a*t²

u= 6 m/s , a= 2 m/s² and t = 12 seconds

S = (6*12 )+ (0.5*2*12²)

S = 72+144

S= 216 meters

Thus, the truck covers a distance of 216 meters.

Learn more about equations of motion from here

brainly.com/question/5955789

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