Respuesta :

gmany
The formula of the midpoint of AC:
[tex]\left(\dfrac{x_A+x_C}{2};\ \dfrac{y_A+y_C}{2}\right)[/tex]

We have A(-2; 4) and C(3; -3). Substitute:
[tex]\left(\dfrac{-2+3}{2};\ \dfrac{4+(-3)}{2}\right)=\left(\dfrac{1}{2};\ \dfrac{1}{2}\right)[/tex]