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Abel was wrapping a gift for an upcoming party. He began with 20 1/2 feet of paper. He used 5 5/12 feet on his first gift and 3 1/3 feet on his second gift. If Abel bought 2 additional rolls of paper that each contained 10 1/2 feet, how many papers does he now have left for wraping.

Respuesta :

Hey there!

[tex]20 \dfrac{1}{2} - 5 \dfrac{5}{12} - 3 \dfrac{1}{3} + 2 \times 10 \dfrac{1}{2} \\ = \dfrac{41}{2} - \dfrac{65}{12} - \dfrac{10}{3} + 21 \\ = \dfrac{246}{12} - \dfrac{65}{12} - \dfrac{40}{12} + 21 \\ = \dfrac{141}{12} + 21 \\ = 32 \dfrac{3}{4} [/tex]

Answer : 32 3/4 feet or in decimal form, 32.75 feet.

Hope this helps. - M
[tex]\text {At first = } 20\dfrac{1}{2} \text{ feet}[/tex]

[tex]\text {Used } 5\dfrac{5}{12} \text{ on the first gift : }[/tex]
[tex]20\dfrac{1}{2} - 5\dfrac{5}{12} [/tex]
[tex]= 20\dfrac{6}{12} - 5\dfrac{5}{12} [/tex]
[tex]= 15\dfrac{1}{12} \text{ feet}[/tex]

[tex]\text {Used } 3\dfrac{1}{3} \text{ on the second gift : }[/tex]
[tex]15\dfrac{1}{12} - 3\dfrac{1}{3} [/tex]
[tex]= 14\dfrac{13}{12} - 3\dfrac{4}{12} [/tex]
[tex]= 11\dfrac{9}{12} [/tex]
[tex]= 11\dfrac{3}{4}\text{ feet}[/tex]

[tex]\text {Bought additional 2 rolls of } 10\dfrac{1}{2} \text{ feet each : }[/tex]
[tex]11\dfrac{3}{4} + 10\dfrac{1}{2} + 10\dfrac{1}{2} [/tex]
[tex] = 11\dfrac{3}{4} + 10\dfrac{2}{4} + 10\dfrac{2}{4} [/tex]
[tex]= 31\dfrac{7}{4}[/tex]
[tex] = 32\dfrac{3}{4} \text{ feet}[/tex]

[tex]\boxed{ \boxed{ \text{Answer: }32\dfrac{3}{4}\text{ feet}}}[/tex]