As in this problem the order of numbers does not matter We are talking about a combination and not to permutation.
So to determine the probability that a set of six randomly selected numbers wins the lottery we need to first draw the combination of 6 in 49 without repetition:
C (49.6) = 49! / (6! (49-6)!) = 13983816
Then there are 13983816 combinations of possible numbers for this case.
Finally the probability is:
p = 1/13983816
p = 7,151 x10 ^ -8
The correct option is the last
