The boat is moving by uniformly accelerated motion, with initial speed
[tex]v_i = 3 m/s[/tex]
constant acceleration of
[tex]a=2 m/s^2[/tex]
and it covers a distance of
[tex]S=10 m[/tex]
So we can use the following relationship to find the final speed, [tex]v_f[/tex]:
[tex]v_f^2 - v_i^2 = 2aS[/tex]
[tex]v_f = \sqrt{v_i^2 + 2aS}= \sqrt{(3 m/s)^2 +2(2 m/s^2)(10 m)} = 7m/s [/tex]
