It is a distance-speed-time problem. Applying the general formula of [tex]s=vt[/tex], we'll solve this problem. If the speed of the second jet is [tex]v[/tex], then the speed of the first jet is [tex]75+v[/tex] according to the problem. The first jet requires 3 hours and 36 minutes (3.6 hours) and the second one 3 hours.
By setting up an equation we can write that [tex]3(v+75) = 3.6v[/tex] and [tex]v=375 [/tex]
The length of flight is [tex]s=vt=375*3.6=[/tex] or [tex]450*3=1350[/tex] miles
