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The railroad crossing lights turn red, so mckayla and her sister must stop and wait for the train to pass by. as they wait, mckayla's sister kylie grabs her phone and uses an app to measure the frequency of the approaching train's horn. the app reads 429 hz. assuming the train's original horn frequency is 400 hz and the speed of sound is 330 m/s, how fast is the train going in m/s and miles per hour

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skyluke89
We can solve the problem by using the Doppler effect formula, which gives us the shift in frequency of a sound when the source is moving:
[tex]f'= ( \frac{v}{v+v_s} ) f[/tex]
where
f' is the apparent frequency
v is the velocity of the wave
[tex]v_s[/tex] is the velocity of the source relative to the observer
f is the original frequency

In our problem, f=400 Hz is the original frequency of the train's horn, f'=429 Hz is the apparent frequency read by the app, and v=330 m/s is the velocity of the wave (the speed of sound). If we re-arrange the formula, we can calculate v, the speed of the train:
[tex]v_s = v ( \frac{f}{f'}-1 )=(330 m/s)( \frac{400 Hz}{429 Hz}-1 )=-22.3 m/s[/tex]
where the negative sign means the train is moving toward the two children.

In miles per hour, the velocity of the train is:
[tex]v=-22.3 \frac{m}{s} \cdot \frac{1/1609 mil/m}{1/3600 h/s}= -49.9 mph [/tex]
onyebuchinnaji

The speed of the approaching train is 23.93 m/s or 53.54 mph.

Doppler effect

The speed of the approaching train can be determined using Doppler effect formula as shown below;

[tex]f_s = f_o (\frac{v\pm v_0}{v\pm v_s} )\\\\400 = 429(\frac{330 + 0}{330 - v_s} )\\\\\frac{400}{429}= \frac{330}{330-v_s} \\\\330-v_s = \frac{330 \times 429}{400} \\\\330-v_s = 353.93 \\\\|v_s |= 353.93 - 330\\\\v_s = 23.93 \ m/s[/tex]

Speed of the train in miles per hour

1 mile = 1609 meters

[tex]v_s = 23.93 \frac{m}{s} \times \frac{1 \ mile}{1609 \ m} \times \frac{3600 \ s}{1 \ hr} \\\\v_s = 53.54 \ mph[/tex]

Learn more about Doppler effect here: https://brainly.com/question/3841958

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