Be sure to use proper significant figures for all remaining problems. how many grams of nacl are present in 350 ml of 0.020 m nacl solution? (remember that 1 mole nacl = 58.44 g/mole.)

Respuesta :

The answer would be 0.41

Explanation:

Molarity is defined as number of moles of solute present in liter of solution.

Mathematically,        Molarity = [tex]\frac{no. of moles}{volume in liter}[/tex]

It is known that 1000 mL equals 1 L so, 350 ml equals 0.35 L. Therefore, calculate no. of moles as follows.

                  Molarity = [tex]\frac{no. of moles}{volume in liter}[/tex]

                        0.020 M = [tex]\frac{no. of moles}{0.35 L}[/tex]

                 no. of moles = 0.007 mol

Also, it is known that no. of moles equal mass divided by molar mass. Molar mass of NaCl is 58.44 g/mol.

Thus, calculate mass of NaCl as follows.

                        No. of moles = [tex]\frac{mass}{molar mass}[/tex]

                        0.007 mol = [tex]\frac{mass}{58.44 g/mol}[/tex]

                             mass = 0.409 g

Thus, we can conclude that 0.409 grams of NaCl are present in 350 ml of 0.020 m nacl solution.