Answer: Probability of Antawn Jamison making all of his next 9 free throw attempts is 0.058 i.e. 5.8%
Step-by-step explanation:
Since we have given that
Probability that he will make his next one and he makes his free throws = 73%
Number of throws = 9
We will use "Binomial distribution":
[tex]P(X=9)=^9C_9(0.73)^9(1-0.73)^{0}\\\\P(X=9)=1\times (0.73)^9(0.27)^0\\\\P(X=9)=0.058[/tex]
Hence, probability of Antawn Jamison making all of his next 9 free throw attempts is 0.058 i.e. 5.8%
