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A 320-m length of wire stretches between two towers and carries a 120-a current. determine the magnitude of the force on the wire due to the earth's magnetic field of 5.0 ×10−5t which makes an angle of 60 ∘ with the wire.

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jushmk
Information provided:
Length of wire, L = 320 m
Current through the wire, I = 120 Amps
Earth's magnetic field acting on the wire, B = 5.0*10^-5 T
Angle at which the magnetic field acts, Ф = 60°

By definition;
Force on the wire, F = LBI Sin Ф

Substituting;
F = 320*5*10^-5*120*Sin 60 = 1.663 N
marianaegarciaperedo

Following the Lorentz force law we can calculate the magnetic force on the wire by using the formula F = ILBsin ∅. The magnitude of the force on the wire is F = 1.663 N

How to get the magnetic force through the wire?

Following the Lorentz force law, we can use the following formula to get the magnetic force,

F = qvB sin ∅

being,

  • F = magnetic force
  • q = charge
  • v = velocity
  • B = magnetic field
  • ∅ = angle

Knowing that

  • velocity, v = L/T
  • current, I, is the amount of charge, q, that flows per second,

Then, qv = IL

So now, we can use the provided information to make the calulations. This is

F = qvB sin ∅ = ILBsin ∅

  • I = 120A
  • L = 320m
  • B = 5.0 ×10⁻⁵
  • ∅ = 60⁰

The force on the wire F can be determined by

F = ILBsin ∅

F = 120A x 320m x 5.0 ×10⁻⁵ x sen60⁰

F = 120 x 320 x 0.00005 x 0.866

F = 1.663 N

The magnitude of the force on the wire is F = 1.663 N

You can learn more about magnetic force at

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