Respuesta :
The motion of the projectile is a composition of two separate motions:
- in the horizontal direction, it is moving by uniform motion, with constant speed [tex]v_x=30 m/s[/tex]
- in the vertical direction, it is moving by uniformly acceleration motion, with initial speed [tex]v_y=40 m/s[/tex] and constant acceleration [tex]g=9.81 m/s^2[/tex] towards the ground
At the highest point of its trajectory, the vertical component of the projectile's velocity is zero: [tex]v_y = 0[/tex], while the horizontal component is still the initial one: [tex]v_x=30 m/s[/tex]. Therefore, the speed of the projectile at its highest point is exactly 30 m/s.
- in the horizontal direction, it is moving by uniform motion, with constant speed [tex]v_x=30 m/s[/tex]
- in the vertical direction, it is moving by uniformly acceleration motion, with initial speed [tex]v_y=40 m/s[/tex] and constant acceleration [tex]g=9.81 m/s^2[/tex] towards the ground
At the highest point of its trajectory, the vertical component of the projectile's velocity is zero: [tex]v_y = 0[/tex], while the horizontal component is still the initial one: [tex]v_x=30 m/s[/tex]. Therefore, the speed of the projectile at its highest point is exactly 30 m/s.
The speed of the projectile when it is at the highest point in its trajectory is of 30 m/s.
What is projectile motion?
The motion of any object at an instant when it is subjected to only the acceleration due to gravity is known as projectile motion.
Given data -
The initial horizontal component of velocity is, u = 30 m/s.
The initial vertical component of velocity is, u' = 40 m/s.
At the highest point of the trajectory, the vertical component of the projectile's velocity is zero (u' = 0), while the horizontal component is still the initial one (u = 30 m/s). Therefore, the speed of the projectile at its highest point is exactly 30 m/s.
Thus, we can conclude that the speed of the projectile when it is at the highest point in its trajectory is of 30 m/s.
Learn more about the projectile motion here:
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