Respuesta :
If we want the object to continue to move at constant speed, it means that the resultant of the forces acting on the object must be zero. So far, we have:
- force F1 with direction north, of 10 N
- force F2 with direction west, of 10 N
The third force must balance them, in order to have a net force of zero on the object.
The resultant of the two forces F1 and F2 is
[tex]F_{12} = \sqrt{F_1^2+F_2^2}= \sqrt{(10 N)^2+(10 N)^2}= \sqrt{200}=14.1 N [/tex]
with direction at [tex]45^{\circ} [/tex] north-west. This means that F3 must be equal and opposite to this force: so, F3 must have magnitude 14.1 N and its direction should be [tex]45^{\circ}[/tex] south-east.
- force F1 with direction north, of 10 N
- force F2 with direction west, of 10 N
The third force must balance them, in order to have a net force of zero on the object.
The resultant of the two forces F1 and F2 is
[tex]F_{12} = \sqrt{F_1^2+F_2^2}= \sqrt{(10 N)^2+(10 N)^2}= \sqrt{200}=14.1 N [/tex]
with direction at [tex]45^{\circ} [/tex] north-west. This means that F3 must be equal and opposite to this force: so, F3 must have magnitude 14.1 N and its direction should be [tex]45^{\circ}[/tex] south-east.
If the object is to conitnue moving to the west at a constant speed then the third force must be equal and opposite to the force [tex]\rm F_R[/tex]. Therefore, the magnitude of the third force is 14.14 N and in the [tex]45^\circ[/tex] south-east direction.
Given :
Force acting on the block in north direction, [tex]\rm F_1 = 10\;N[/tex]
Force acting on the block in west direction, [tex]\rm F_2 = 10\;N[/tex]
Solution :
To find third force so that the object is to conitnue moving to the west at a constant speed we have to first find the resultant of [tex]\rm F_1\;and \;F_2[/tex]
[tex]\rm F_R = \sqrt{F_1^2 +F_2^2}[/tex]
[tex]\rm F_R = \sqrt{10^2+10^2} = 14.14\;N[/tex]
Now,
[tex]\rm tan\theta = \dfrac{10}{10}=1[/tex]
[tex]\theta = 45^\circ[/tex]
So, the resultant force acting is 14.14 N and in the [tex]45^\circ[/tex] north-west direction. If the object is to conitnue moving to the west at a constant speed then the third force must be equal and opposite to the force [tex]\rm F_R[/tex]. Therefore, the magnitude of the third force is 14.14 N and in the [tex]45^\circ[/tex] south-east direction.
For more information, refer the link given below
https://brainly.com/question/16380983?referrer=searchResults
