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A population numbers 15,000 organisms initially and grows by 12.4% each year. Suppose P represents population, and t the number of years of growth. write the function in terms of t.

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JeanaShupp

Answer: [tex]P=15000(1.124)^t[/tex]

Step-by-step explanation:

The exponential growth equation with rate of growth r in time period t is given by :-

[tex]y=A(1+r)^t[/tex], where A is the initial amount

Given : The rate of growth of population every year : 12.4% =0.124

The initial population of organisms= 15,000

Let  P represents population, and t the number of years of growth.

Then , the exponential growth equation in time period t is given by :-

[tex]P=15000(1+0.124)^t\\\\\Rightarrow\ P=15000(1.124)^t[/tex]

aksnkj

Answer:

The population as a function of time will be [tex]P=15000+0.124t[/tex].

Step-by-step explanation:

The initial population of the organism is, [tex]C=15000[/tex]

The rate of growth of the population is, [tex]r=12.4\%[/tex] each year.

Let the final population of the organism is [tex]P[/tex]. And [tex]t[/tex] represents the number of years of growth.

So, the population of the organism after [tex]t[/tex] years of growth can be written as,

[tex]P=C+rt\\P=15000+\dfrac{12.4}{100}\times t\\P=15000+0.124t[/tex]

Therefore, the population as a function of time will be [tex]P=15000+0.124t[/tex].

For more details, refer the link:

https://brainly.com/question/14966102?referrer=searchResults

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