find the probability that a point chosen randomly inside the rectangle is in each given shape. Round answers to the nearest hundreth. I need the percent.
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9) 20.93%
10) 20%
11) 40.93%
12) 59.07%
We are given a rectangle of dimensions 10ft×6ft which inscribes:
Hence,
Here we have: r= 2ft.
Hence, Area of circle=(3.14)×(2)²
= 12.56 square ft.
=1/2×(4+2)×4
= 12 square ft.
= 10×6
= 60 square ft.
Ques 9)
Probability that a point chosen lie on circle is:
Area of circle/Area of rectangle
= 12.56/60
= 0.2093333
In percent it is given by: 20.93%
Ques 10)
Probability that a point chosen lie on trapezoid is:
Area of trapezoid/Area of rectangle
= 12/60
= 0.2
In percent it is given by: 20%
Ques 11)
The circle or trapezoid is:
Probability that a point is chosen on circle+Probability that it is chosen on trapezoid.
= 40.93%
( Since,
P(A∪B)=P(A)+P(B)-P(A∩B)
and as circle and trapezoid do not have anything in common.
Hence, A∩B=∅
Hence, P(A∩B)=∅
Hence, P(A∪B)=P(A)+P(B) )
Ques 12)
Not the circle and the trapezoid this means that the point will lie in the shaded region.
Hence, Probability is:
100%-Probability(it will lie either on circle or trapezoid)
=100%-40.93%
=59.07%