Respuesta :
[tex]f(x)=2x^2+3\\\\g(x)=x^2-7\\\\(f-g)(x)=(2x^2+3)-(x^2-7)=2x^2+3-x^2+7=x^2+10[/tex]
Answer: C) x² + 10
Answer: C) x² + 10
Answer:
The answer is C.)x^(2)+10
Step-by-step explanation:
Given:
F(x)=2x^(2)+3, and
g(x)=x^(2)-7,
In order to find (f-g)(x), we have to subtract g(x) from f(x), thus: f(x) - g(x) = (f-g)(x) = 2x^(2)+3 - (x^(2)-7) = 2x^(2)+3 - x^(2)+7 = 2x^(2)- x^(2)+3+7 = x^(2)+10