contestada

HELP ASAPP PLEASEE

The electric field intensity between two charged plates is 4.1 x 10 N/C. The plates are 0.01 m apart. What is the potential difference between the plates in volts?

Respuesta :

limacharliesierra
To calculate the Potential Difference between the plates in an Uniform Electric Field we have the formula:
[tex]u = e \times d[/tex]
U = Potential difference = ?
E = Electric Field = 4.1 x 10 N/C
D = Distance = 0.01m = 1 x 10^-2 m

[tex]u = (4.1 \times 10) \times (1 \times 10^{ - 2}) \\ u = 41 \times 10^{ - 2} \: volts \: or \: \: 0.41 \: volts[/tex]
daliamunoz2002

Answer: It can be moved 0.01 m toward the negative plate.  

Explanation: I just took the test.

!!!!!!!