The volume of the cylinder is [tex]\boxed{288\pi {\text{ unit}}{{\text{s}}^3}}[/tex].Option (C) is correct.
Further explanation:
Given:
Theheight of the cylinder is [tex]{\text{8 units}}[/tex] and the radius of the cylinder is [tex]{\text{6 units}}.[/tex]
The options of the volume are given as follows.
A. [tex]{\text{216}}\pi {\text{uni}}{{\text{t}}^3}[/tex]
B. [tex]324\pi {\text{uni}}{{\text{t}}^3}[/tex]
C. [tex]288\pi {\text{uni}}{{\text{t}}^3}[/tex]
D. [tex]432\pi {\text{uni}}{{\text{t}}^3}[/tex]
Explanation:
The formula for the volume of the cylinder can be expressed as,
[tex]\boxed{{\text{Volume}} = \pi {r^2}h}[/tex]
‘r” is the radius of the cylinder and “h” is the height of the cylinder.
The volume of the right cylinder can be obtained as follows,
[tex]\begin{aligned}{\text{Volume}} &= \pi {r^2}h\\&= \pi\times {\left( 6 \right)^2} \times 8\\&= \pi\times 36 \times 8\\&=288\pi \\\end{aligned}[/tex]
The volume of the cylinder is [tex]36\pi {\text{ unit}}{{\text{s}}^3}.[/tex]
The volume of the cylinder is [tex]\boxed{288\pi {\text{ unit}}{{\text{s}}^3}}[/tex].Option (C) is correct.
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Answer details:
Grade: High School
Subject: Mathematics
Chapter: Mensuration
Keywords: Cylinder, surface area of the cylinder, volume of the cylinder, right cylinder, height, radius depth.
