Respuesta :
partial pressure of A= 1.31atm
partial pressure of B= 0.44 atm
just did this chem assignment on edgenuty so i know this is right
partial pressure of B= 0.44 atm
just did this chem assignment on edgenuty so i know this is right
Answer : Partial pressure of gas A is 1.31 atm and that of gas B is 0.44 atm.
Explanation :
The partial pressure of a gas in a mixture can be calculated as
[tex] P_{i}= X_{i}\times P [/tex]
Where Pi is the partial pressure ; Xi is mole fraction and P is the total pressure of the mixture.
Therefore we have
,
[tex] P_{A} = X_{A} \times P [/tex]
[tex] P_{B} = X_{B} \times P [/tex]
Let us find [tex] X_{A} [/tex] and [tex] X_{B} [/tex]
[tex] X_{A} = \frac{mol A}{total moles} = \frac{2.50 mol}{(2.50 + 0.85)mol} = \frac{2.50 mol}{3.35mol} = 0.746 [/tex]
[tex] X_{B} = \frac{mol B}{total moles} = \frac{0.85 mol}{(2.50 + 0.85)mol} = \frac{0.85 mol}{3.35mol} = 0.254 [/tex]
Total pressure P is given as 1.75 atm.
Let us plug in the mole fractions and P values to find partial pressures of gas A and B.
[tex] P_{A} = X_{A} \times P [/tex]
[tex] P_{A} = 0.746 \times 1.75 [/tex]
[tex] P_{A} =1.31 atm [/tex]
Partial pressure of gas A is 1.31 atm
[tex] P_{B} = X_{B} \times P [/tex]
[tex] P_{B} = 0.254 \times 1.75 [/tex]
[tex] P_{A} = 0.44 atm [/tex]
Partial pressure of gas B is 0.44 atm.
Therefore, partial pressures of gas A and B are 1.31 atm and 0.44 atm respectively.
