The sides of the given triangle are [tex] a=21,b=47,c=52 [/tex].
By the Pythagorean Theorem, in a right triangle, the square of the hypotenuse (the larger side) of a right triangle, is the sum of the squares of the other two sides. That is,
[tex] c^2=a^2+b^2 [/tex].
The larger side given in the problem is [tex] c=52 [/tex] , therefore, we have:
[tex] a^2+b^2 =21^2+47^2=2650 \neq 52^2=2704 [/tex].
The Pythagorean identity is not satisfied.
Therefore, the triangle is not a right angled triangle.
