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The figure above shows a DC motor that contains a series field winding (F1) with a resistance of 10 , a parallel field winding (F2) with a resistance of 20 , and an armature with a resistance of 2 . What is the total resistance of this motor?

A. 24
B. 16.4
C. 11.82
D. 32

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OxusTheBrain
soooooooooooooooo you need to click c to get the right answer

 

Answer:

C. 11.82

Explanation:

In this motor, we have the F1 wielding with a resistance of 10 in series with the parallel of F2, with a resistance of 20, and the armature with a resistance of 2.

So, the rotal resistance of this motor is:

[tex]R = 10 + (20//2)[/tex]

[tex]R = 10 + \frac{20*2}{20+2}[/tex]

[tex]R = 10 + 1.82[/tex]

[tex]R = 11.82[/tex]

So the correct answer is:

C. 11.82

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