The vector written in its generic form is given by: v = lvl cos theta ° i + lvl without theta ° j Where. lvl: magnitude of the vector theta: angle of the vector with respect to the x axis. For this case we have the following vector: v = 3 cos 123 ° i + 3 without 123 ° j Where, lvl = 3 theta = 123 ° Answer: The magnitude and direction angle for the vector v is: D. 3, 123 °
