Respuesta :
Answer is: c. MgSO₃.
In magnesium sulfite, magnesium has oxidation number +2, sulfur has oxidatidion number +4 and oxygen -2:
+2 + (+4) + 3·(-2) =0.
a) in calcium sulfide, calcium has oxidation number +2 and sulfur -2:
+2 + (-2) = 0.
b) in sodium nitride, sodium has oxidation number +1 and nitrogen -3:
3 · (+1) + (-3) = 0.
d) in aluminium nitrite, aluminium has oxidation number +3, nitrogen +3 and oxygen has -2:
+3 + (+3 + 2 · (-2)) · 3 = 0.
In magnesium sulfite, magnesium has oxidation number +2, sulfur has oxidatidion number +4 and oxygen -2:
+2 + (+4) + 3·(-2) =0.
a) in calcium sulfide, calcium has oxidation number +2 and sulfur -2:
+2 + (-2) = 0.
b) in sodium nitride, sodium has oxidation number +1 and nitrogen -3:
3 · (+1) + (-3) = 0.
d) in aluminium nitrite, aluminium has oxidation number +3, nitrogen +3 and oxygen has -2:
+3 + (+3 + 2 · (-2)) · 3 = 0.
Oxidation number is defined as the degree of an atom to lose electrons in a compound. In the given compounds, the highest oxidation number will be of Magnesium sulfite or MgSO[tex]_{3}[/tex].
Oxidation state or number of magnesium sulfite can be is calculated as:
- Magnesium or Mg has an oxidation number of +2.
- Sulfur or S has an oxidation number of +4.
- Oxygen or O has an oxidation number of -2.
Now, summing up the oxidation states, we get:
+ 2 + (+4) + 3 (-2) = 0.
Thus, the magnesium is the atom with highest oxidation number of +4.
Reasons for incorrect answers:
- Calcium sulfide has the oxidation states as +2 and -2, for calcium and sulfur, respectively, such that :2 + (-2) = 0.
- Similarly, in sodium nitride, sodium has oxidation number +1 and nitrogen -3, such that: 3 (+1) + (-3) = 0.
- Also, in aluminium nitrite, aluminium has oxidation number +3, nitrogen +3 and oxygen has -2:, that can written as: +3 + (+3 + 2 (-2)) (3) = 0.
Therefore, magnesium has the highest oxidation number in the given compounds.
To know more about oxidation states, refer to the following link:
https://brainly.com/question/10079361?referrer=searchResults
