Comment
I'm going to assume that 0 is below 1 and not above 9. Furthermore that there are 10 digits altogether.
Argument
I may not understand the problem, but I think it means that how many students will randomly choose an 8 or 9.
Since both can come up (randomly) 1/10 of the time, it would seem to me that the answer should be
1/10 * 25 + 1/10 * 25 = 5
so 5/25 students will come up with an 8 or 9.
so P(8 or 9) = 0.2 <<<< answer
Note
Any two digits should give you the same result.
