Answer:
balanced equation for the neutralisation reaction is as follows
NaOH + HNO₃ --> NaNO₃ + H₂O
stoichiometry of NaOH to HNO₃ is 1:1
number of NaOH moles to be neutralised is - 0.100 mol/L x 0.1500 L = 0.015 mol
therefore number of HNO₃ moles reacted - 0.015 mol
molarity of HNO₃ solution is 0.120 M
volume of solution in which there 0.120 mol - 1 L
then 0.015 mol are in - 0.015 mol / 0.120 mol/L = 125 mL
volume of HNO₃ required - 125 mL
Explanation:
