Respuesta :
Following reaction is involved in above question:
TiO2 + 2Cl2 → TiCl4 + O2
(1 mole) (2 mole)
In the above reaction, it can be seen that 1 mole of TiO2 reacts with 2 mole of Cl2 to form 1 mole of TiCl4.
∴ 1.25 mole of TiO2 will react with 2.5 mole of Cl2 to form 1 mole of TiCl4.
Now, 1 mole of Cl2 = 70 g
∴ 2.5 mole of Cl2 = 70 X 2.5 = 175 g
Thus, for complete reaction of 1.25 mole of TiO2, 175 g of Cl2 will be required.
TiO2 + 2Cl2 → TiCl4 + O2
(1 mole) (2 mole)
In the above reaction, it can be seen that 1 mole of TiO2 reacts with 2 mole of Cl2 to form 1 mole of TiCl4.
∴ 1.25 mole of TiO2 will react with 2.5 mole of Cl2 to form 1 mole of TiCl4.
Now, 1 mole of Cl2 = 70 g
∴ 2.5 mole of Cl2 = 70 X 2.5 = 175 g
Thus, for complete reaction of 1.25 mole of TiO2, 175 g of Cl2 will be required.
Answer:
The correct answer is 175 grams of Chlorine is required.
Explanation:
The reaction for the given case is:
TiO₂ (1 mole) + 2Cl₂ (2 mole) → TiCl₄ + O₂
From the reaction, it can be observed that 1 mole of TiO₂ reacts with 2 mole of Cl₂ to produce 1 mole of TiCl₄.
Therefore, 1.25 mole of TiO₂ will react with 2.5 mole of Cl₂ to produce 1 mole of TiCl₄.
The molecular weight of 1 mole of Cl₂ is 70 g
Thus, 2.5 mole of Cl₂ = 70 × 2.5 = 175 g
Therefore, for complete reaction of 1.25 mole of TiO₂, 175 g of Cl₂ will be needed.