Answer:
Density = 1.13 g/L
Solution:
Data Given;
Pressure = P = 0.97 atm
Temperature = T = 39.9 °C + 273 = 312.9 K
M.mass of NO = M = 30 g/mol
Gas Constant = R = 0.0821 atm.L.mol⁻¹.K⁻¹
Formula Used,
Density = P M / R T
Putting values,
Density = (0.97 atm × 30 g.mol⁻¹) ÷ (0.0821 atm.L.mol⁻¹.K⁻¹ × 312.9 K)
Density = 1.13 g/L