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Answer:
The probability is 1/8 or 0.125.
Step-by-step explanation:
Given is that three fair coins are flipped.
And we have to find the probability of getting a head on the first flip,a tail on the second flip, and another head on the third flip.
Firstly, here each flip is independent of the outcome of the other flips.
So, the probability of head is 1/2 and the probability of tail is 1/2.
Therefore, the answer will be :
[tex](1/2)(1/2)(1/2)=1/8[/tex]
You can count the total number of outcomes in flip of three coins and can count the count of favorable event. This will help achieve the real probability.
The needed probability is [tex]\dfrac{1}{8}[/tex]
How to calculate total number of outcomes in flip of three coins?
There are two outcomes in single coin's flip(head and tail).
For each outcome of first coin, there can be two outcome of second , thus having 2 times 2 = 4 outcomes.
For each one of those 4 outcomes, the third coin has 2 outcomes ,thus 4 times 2 = 8 outcomes.
Thus, in total, we have 8 possible results of flip of 3 coins.
How to identify how many elements are there in the favorable event?
The favorable event needs first coin and third coin to output head and second coin needs to have tail. This thing specified all three coins and all three coins have no options but only one - one choice. Thus total [tex]1 \times 1 \times 1 = 1[/tex] is the count of elements in favorable event.
Thus, by using definition of probability of an event, we get:
[tex]P(Favorable \: Event) = \dfrac{\text{Number of favorable cases}}{\text{Number of total cases}}\\P(Favorable \: Event) = \dfrac{1}{8}[/tex]
Thus,
The needed probability is [tex]\dfrac{1}{8}[/tex]
Learn more about probability here:
https://brainly.com/question/1210781
