Respuesta :
450/25= 18
where 450 is $4.50 and 25 is one quarter. there will be 18 quarters.
560-450=110
110/10=11
where 110 is $1.10 and 10 is one dime. there will be 11 dimes.
11+18= 29
where 11 is total number of dimes and 18 is total number of quarters. and 29 is total number of coins
where 450 is $4.50 and 25 is one quarter. there will be 18 quarters.
560-450=110
110/10=11
where 110 is $1.10 and 10 is one dime. there will be 11 dimes.
11+18= 29
where 11 is total number of dimes and 18 is total number of quarters. and 29 is total number of coins
When working problems of this sort, it is usually convenient to let the variable represent the highest-value contributor. Here, we choose to let q represent the number of quarters. Then the number of dimes is (29 -q) and the total value is
25q +10(29 -q) = 560 . . . . . . . . . . value in cents
15q = 560 -290
q = 270/15 = 18
As we said, the number of dimes is 29 -q = 11.
I have 18 quarters and 11 dimes.
25q +10(29 -q) = 560 . . . . . . . . . . value in cents
15q = 560 -290
q = 270/15 = 18
As we said, the number of dimes is 29 -q = 11.
I have 18 quarters and 11 dimes.