Respuesta :
Answer:
[tex]XPO4[/tex]
Explanation:
First off, what is the chemical formula of the phosphate ion?
The formula of a phosphate ion is given as; (PO4)3−
The phosphate ion is a polyatomic ion with the empirical formula (PO4)3−
and a molar mass of 94.97 g/mol. It consists of one central phosphorus atom surrounded by four oxygen atoms in a tetrahedral arrangement. The phosphate ion carries a −3 formal charge.
With a formal charge of -3, it means the ion would have to gain 3 electrons when entering into a bond in order for it to be neutral.
X on the other hand as an electronic configuration of 2-8-3. The electron configuration reveals X has a valency (Number of electrons in the outermost electron shell) of 3. As such, X is a group 3 element (Aluminium to be much precise).
With valency of 3 it means X is willing and able to lose its 3 electrons to enter into a bond.
This leads to the formular between X and the phosphate ion to be [tex]X^{3}(PO4)^{-3}[/tex]. XPO4
The formal charges balances each other (3 - 3 = 0). This means the total number of electrons lost by X is the total number of electrons received by the phosphate ion.
The electron configuration is the distribution of electrons in the atomic or molecular orbitals of an atom or molecule.
The compound that is formed is [tex]\bold{XPO_4}[/tex]
What is a phosphate ion?
A core phosphorus atom is surrounded by four oxygen atoms in a tetrahedral arrangement in the phosphate ion, which has a molar mass of 94.97 g/mol.
The formula of a phosphate ion is [tex](PO_4)3^-[/tex]
It has a molar mass of 94.97 g/mol. In a tetrahedral structure, one core phosphorus atom is surrounded by four oxygen atoms.
The formal charge of the phosphate ion is -3 which means the ion has to gain 3 electrons to get neutral.
Now,
As given, X has an electronic configuration of 2-8-3. According to the electron, configuration, X has a valency of 3 (number of electrons in the outermost electron shell). As a result, X has been classified as a group 3 elements.
With a valency of 3, X is able to lose or gain its 3 electrons to form a bond.
The formal charges are in equilibrium (3 - 3 = 0). This means that X's total number of electrons lost equals the phosphate ion's total number of electrons received.
Thus, this means that the compound is [tex]\bold{XPO_4}[/tex].
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