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sarkhan2018
We have this parallelogram shown in the picture (just ignore the letters). Let's  DK (in the picture it is AC) with x and CD (in the picture it is AD) with x-7. Applying Pythagoras theorem, we can write that DA (in the problem, in the picture it is AE) is [tex]DA^{2} = (x-7)^{2} - 36 = x^{2} - 225 [/tex]. Solving this equation, we find the value of x and it is 106/7. That's the value of DK. And CD=106/7-7=57/7
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If I understand the question correctly, then we have 2 right triangles; 
ΔDAC and ΔDAK. To make our lives easier, we denote CD as x, DK as x+7, and DA as y. Since CA=6 and AK=15, we use the Pythagorean Theorem:
ΔDAC; CA²+DA²=CD²=   6²+y²=x² 
ΔDAK; CA²+AK²=DK²=    15²+y²=(x+7)²
Using these two equations, we find that CD equals 10 and DK equals 17.
Hope it helps!

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