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Two boys divided $3.36 so that one boy received 12 cents less than three times as much as the other. How was the money divided?

Respuesta :

sarkhan2018
Let's first convert that amount of money into cents, which makes 336 cents. Then, let's denote the amount of money one of the boys has with x. The other boy has got 3x-12 amount of money. We can construct an equation. [tex]3x-12+x=336[/tex]. Solving it we find that x=87 cents or $ 0.87 and the other boy holds $2.49 amount of money.
ashishdwivedilVT

One boy received 87 cents while another boy received 249 cents.

Let us assume one boy received x cents.

What is the subtraction of a variable X and integer I?

The subtraction of a variable X and integer I is X-I

So other will receive = 3x-12

As we know that there are 336 cents ie $3.36*100.

Total cents =336

x+3x-12 = 336

4x=348

x=87

So, one boy received 87 cents.

Number of cents received by another = 3x-12 = 3*87-12=249 cents.

Therefore, one boy received 87 cents while another boy received 249 cents.

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