contestada

"a 0.850-mole sample of nitrous oxide, a gas used as an anesthetic by dentists, has a volume of 20.46 l at 123°c and 1.35 atm. what would be its volume at 468°c and 1.35 atm?"

Respuesta :

Charles law states that volume of gas is directly proportional to volume of gas at constant pressure  
[tex] \frac{V1}{T1} = \frac{V2}{T2} [/tex]
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 
where 
V - volume 
T - temperature in kelvin
T1 - 123 °C + 273 = 396 K
T2 -  468 °C + 273 = 741 K
substituting the values
[tex] \frac{20.46L}{396K}= \frac{V}{741K} [/tex]
V = 38.29 L 
new volume is 38.29 L
CintiaSalazar

Considering the Charles's law, the volume at 468°c and 1.35 atm is 38.285 L.

Charles's law

Charles' Law consists of the relationship that exists between the volume and the temperature of a certain amount of ideal gas, which is maintained at a constant pressure.

So, for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases. That is, the volume is directly proportional to the temperature of the gas.

In summary, Charles' law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

[tex]\frac{V}{T} =k[/tex]

It is desired to study two different states, an initial state 1 and a final state 2, and the following will be true:

[tex]\frac{V1}{T1} =\frac{V2}{T2}[/tex]

Volume at 468°c and 1.35 atm

In this case, you know:

  • V1= 20.46 L
  • T1= 123 °C= 396 K (being 0 C= 273 K)
  • V2= ?
  • T2= 468 °C= 741 K

Replacing on Charles's law:

[tex]\frac{20.46 L}{396 K} =\frac{V2}{741 K}[/tex]

Solving:

[tex]V2=741 K\frac{20.46 L}{396 K}[/tex]

V2= 38.285 L

Finally, the volume at 468°c and 1.35 atm is 38.285 L.

Learn more about Charles's law:

https://brainly.com/question/4147359

Otras preguntas