Answer:
try this 3x+4y=-5
6x+2y=8
3x+y=16
Step-by-step explanation:
The equation of a line that is perpendicular to y=-0.3x+6 and that passes through the point (3,-8) is 3y - 10x = -54
The equation of a line in point-slope form is expressed as:
y-y0 = m(x-x0)
m is the slope
(x0, y0) is the point on the line
Given the equation y = -0.3x + 6
Slope m = -0.3
The slope of the line perpendicular = -1/-0.3 = 1/0.3 = 10/3
Get the required equation:
y - (-8) = 10/3 (x - 3)
y + 8 = 10/3(x-3)
3(y + 8) = 10(x - 3)
3y + 24 = 10x - 30
3y - 10x = -30 - 24
3y - 10x = -54
Hence the equation of a line that is perpendicular to y=-0.3x+6 and that passes through the point (3,-8) is 3y - 10x = -54
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