Respuesta :

CarlosRCR
There are two -main- approaches to answer this problem. By using the sine identity, or applying law of sines.

We'll do the sine trig. identity, as it is the most effective.

Given an angle '[tex] \alpha [/tex]' in a right triangle, '[tex]sin( \alpha )[/tex]' is defined as the opposite side of the triangle to the given angle, over the triangle's hypotenuse.

So, for this setup:
[tex]sin(20)= \frac{x}{10} [/tex]

Now, we solve for x:
[tex]x=10sin(20)=3.42[/tex]

So, answer is 3.4
aencabo
The given triangle is a right angle. To solve this, we can use;

sin theta = opposite / hypotenuse ; where theta =20 ; h = 10
sin (20) = x / 10
x = 3.42

The answer is the fourth one, 3.42

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