A pyramid has a regular hexagonal base with side lengths of 4 and a slant height of 6. Find the total area of the pyramid.
T. A. =
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Answer:
Step-by-step explanation:
alright lets get started.
Total area of pyramid will be equals to the sum of area of base and the area of all six faces.
area of hexagonal will be = [tex]\frac{3\sqrt{3} }{2} *a^2[/tex]
Plugging the value of a as 4, the area of base will be :
[tex]\frac{3\sqrt{3} }{2}*4^2= 41.57[/tex]
Now the area of one face will be= [tex]\frac{1}{2} *base*height[/tex]
so, the area of one face will be = [tex]\frac{1}{2} * 4*6=12[/tex]
So, the area of six faces will be = [tex]6*12=72[/tex]
So, the total area of pyramid will be = [tex]41.57+72[/tex]
So, the total area of pyramid will be 113.57
Hence the answer is 113.57. : answer
Hope it will help :)