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In 2000, the circulation of a local newspaper was 3,250. In 2001, its circulation was 3,640. In 2002, the circulation was 4,100. a. Find the percent of increase in the newspaper’s circulation from 2000 to 2001 and from 2001 to 2002. b. Which period had a higher percent of increase, 2000 to 2001, or 2001 to 2002?

Respuesta :

celestialscienc

The formula for percentage change is:

(New number - Original number) / Original number × 100 = Percentage change


(3640-3250)/3250 x 100 =
(390)/3250 x 100 =
.12 x 100 = 12%

(4100-3640)/3640 x 100 =
(460)/3640 x 100 =
.1263736264 x 100 = ~ 12.6%

2001 to 2002 had a higher percent of increase.


adioabiola

The percent of increase in the newspaper’s circulation from 2000 to 2001 and from 2001 to 2002 is 12% and 12.6% respectively

Given:

2000 = 3,250

2001 = 3,640

2002 = 4,100

Percentage change2000 to 2001 = (Difference in change) / old value × 100

= (3,640 - 3,250) / 3,250 × 100

= 390 / 3,250 × 100

= 0.12 × 100

= 12%

Percentage change 2001 to 2002 = (Difference in change) / old value × 100

= (4,100 - 3,640) / 3,640 × 100

= 460 / 3,640 × 100

= 0.126373626373626 × 100

= 12.63736263736263%

Approximately,

12.6%

Therefore, the period which had a higher percent of increase is 2001 to 2002

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