Respuesta :

gmany
10 + 5 + 1 = 16 - all balls
The probability that the first ball is red: [tex]P(R)=\dfrac{10}{16}=\dfrac{5}{8}[/tex]
The probability that the second ball is black: [tex]P(B)=\dfrac{1}{15}[/tex]
Together:[tex]P(R)\cdot P(B)=\dfrac{5}{8}\cdot\dfrac{1}{15}=\dfrac{1}{24}[/tex]

awesomeaudge
10 + 5 + 1 is 16. There are 10 red balls, and there are 16 balls altogether. If you’re asking for a fraction, it would be 10/16. 10/16 as a simplified fraction is 5/8. The probability that the first ball is red is 5/8. There is one black ball, and 16 altogether. If you’re asking for a fraction, it would be 1/16. 1/16 can’t be simplified anymore because it is already in its lowest terms. So the probability of drawing out a black ball is 1/16.
So your answers are....

First ball being red: 5/8

Second ball being black: 1/16

Hoped this helped. Have a nice day!

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