Respuesta :
Hello!!!!
Find the volume of the bottom and top separately and then add them. Cylinder volume is the area of the bottom times the height (22/7)(5^2)•175=13750 ft^3
The volume of a sphere isV=(4/3)(22/7)r^3where r is the radius. Here that's also 5 since it fits on the cylinder. Also we only want half the sphere so useV=(2/3)(22/7)•5^3=261.9 ft^3Which we round upto 262. Now add the parts together 13750+262=14,012 ft^3
Hope this helps!
Find the volume of the bottom and top separately and then add them. Cylinder volume is the area of the bottom times the height (22/7)(5^2)•175=13750 ft^3
The volume of a sphere isV=(4/3)(22/7)r^3where r is the radius. Here that's also 5 since it fits on the cylinder. Also we only want half the sphere so useV=(2/3)(22/7)•5^3=261.9 ft^3Which we round upto 262. Now add the parts together 13750+262=14,012 ft^3
Hope this helps!
Answer:
19460 cubic feet
Step-by-step explanation:
Since we are given that Grain silo is formed by cylinder and a half sphere on top
We are required to find the volume of grain that could completely fill this silo
Formula of volume of cylinder :[tex]\pi r^{2}h[/tex]
Since we are given that the cylinder with which the silo is formed has height 168 feet and radius 6 feet
So, r = 6 feet
h = 168 feet
use π =22/7
Substituting these values in formula
Volume of cylinder [tex]= \frac{22}{7}*(6)^{2} * 168[/tex]
[tex]= \frac{22}{7}*36* 168[/tex]
[tex]= 19008 feet^{3}[/tex]
Thus the volume of cylinder is 19008 cubic feet.
Now since the silo is fomed of half sphere also
Formula of volume of sphere [tex]=\frac{4}{3} \pi r^{3}[/tex]
Volume of half sphere [tex]=\frac{\frac{4}{3}}{2} \pi r^{3}[/tex]
[tex]=\frac{2}{3} \pi r^{3}[/tex]
Since r = 6 feet
So, volume of half sphere [tex]=\frac{2}{3} * \frac{22}{7}*(6)^{3}[/tex]
[tex]=452.57[/tex]
Thus the volume of half sphere is 452.57 cubic feet.
Thus the volume of the grain = volume of cylinder +volume of half sphere
=19008+452.57
=19460.57 cubic feet
Hence the volume of grain that could completely fill this silo is 19460 cubic feet ( rounded to the nearest whole number )
