Standard entropy of the compounds of interest are as follows,
[tex] S^{0} (C6H12O6) [/tex] = 212.1 J/K.mol
[tex] S^{0} (O2) [/tex] = 205.0 J/K.mol
[tex] S^{0} (CO2) [/tex] = 213.6 J/K.mol
[tex] S^{0} (H2O) [/tex] = 69.9 J/K.mol
Now for the reaction:
C6H12O6(s) + 6O2(g) —->6CO2(g) + 6H2O(l)
ΔS°reaction = ∑[tex] S^{0} products [/tex] - ∑[tex] S^{0} reactants [/tex]
∴ ΔS°reaction =( 6 [tex] S^{0} (CO2) [/tex] + 6 [tex] S^{0} (H2O) [/tex] ) - ([tex] S^{0} (C6H12O6) [/tex] + 6 [tex] S^{0} (O2) [/tex] = 205.0 J/K.mol)
∴ ΔS°reaction = [6 (213.6) + 6 (69.9 )] - [(212.1) + 6(205.0)]
∴ ΔS°reaction = 258.9
