Cameron used 1 3/4 ounces of hydrochloric acid in one experiment. She used 2 1/8 ounces of the acid in a second experiment. How much more acid did Cameron use in the second experiment?

Respuesta :

3/8ths more
2 1/8 -1 3/4 =
17/8 - 14/8 = 3/8ths

Answer:

Amount required is [tex]x=\frac{3}{8}[/tex]

Step-by-step explanation:

Given : Cameron used [tex]1\frac{3}{4}[/tex] ounces of hydrochloric acid in one experiment. She used [tex]2\frac{1}{8}[/tex] ounces of the acid in a second experiment.

To find : How much more acid did Cameron use in the second experiment?

Solution :

In one experiment,

Cameron used [tex]1\frac{3}{4}[/tex] ounces of hydrochloric acid

i.e [tex]1\frac{3}{4}=\frac{7}{4}[/tex]

In second experiment,

She used [tex]2\frac{1}{8}[/tex] ounces of the acid.

i.e. [tex]2\frac{1}{8}=\frac{17}{8}[/tex]

Let x amount more she used then experiment 1 in experiment 2.

So, the equation became

[tex]\frac{7}{4}+x=\frac{17}{8}[/tex]

[tex]x=\frac{17}{8}-\frac{7}{4}[/tex]

[tex]x=\frac{17-14}{8}[/tex]

[tex]x=\frac{3}{8}[/tex]

Therefore, Amount required is [tex]x=\frac{3}{8}[/tex]