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  • 11-05-2018
  • Mathematics
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What is the inverse of the function f(x)= 19/x^3 ?

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gmany
gmany gmany
  • 13-05-2018
[tex]f(x)=\dfrac{19}{x^3}\to y=\dfrac{19}{x^3}\\\\\dfrac{y}{1}=\dfrac{19}{x^3}\ \ \ \ |cross\ multiply\\\\yx^3=19\ \ \ \ |:y\neq0\\\\x^3=\dfrac{19}{y}\to x=\sqrt[3]{\dfrac{19}{y}}[/tex]
Answer: [tex]f^{-1}(x)=\sqrt[3]{\dfrac{19}{x}}[/tex]

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