Respuesta :
[tex]|SR|=4\sqrt2;\ |QR|=\sqrt{10}\\\\P=2\cdot4\sqrt2+2\cdot\sqrt{10}=8\sqrt2+2\sqrt{10}[/tex]
Answer: [tex]B.\ 8\sqrt2+\sqrt{10}[/tex]
Answer: [tex]B.\ 8\sqrt2+\sqrt{10}[/tex]