Respuesta :

gmany
[tex]\dfrac{c-5}{c^2-25}\\\\use:\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{c-5}{(c-5)(c+5)}=\dfrac{1}{c+5}[/tex]

For this case we have the following expression:

[tex] \frac{c-5}{c^2-5} [/tex]

To simplify the expression, the first thing to do is factor the denominator.

We have then:

[tex]\frac{c-5}{(c-5)(c+5)}[/tex]

Then, canceling similar terms we have:

[tex]\frac{1}{(c+5)}[/tex]

From here, we must find any value that should be excluded from the expression.

We must exclude values of c that make the denominator equal to zero.

We have then:

[tex] c+5=0

c=-5 [/tex]

Answer:

The simplified expression is:

[tex]\frac{1}{(c+5)}[/tex]

The value to be excluded from the expression is:

[tex] c=-5 [/tex]