Hello!
Rubbing alcohol is 70.0% isopropyl alcohol by volume. how many ml of isopropyl alcohol are in a full 1 pint (473 ml) container?
We have the following information:
% V/V (percentage of volume per volume) = 70
V1 (solute volume) = ? (in mL)
V (volume of the solution) = 473 mL
We apply the data to the formula of volume percentage of the solute per volume of solution, we will have:
[tex]\%\:v/v = \dfrac{v_1}{v} *100[/tex]
[tex]70 = \dfrac{v_1}{473}*100[/tex]
[tex]70*473 = 100*v_1[/tex]
[tex]33110 = 100\:v_1[/tex]
[tex]100\:v_1 = 33110[/tex]
[tex]v_1 = \dfrac{3311\diagup\!\!\!\!0}{10\diagup\!\!\!\!0}[/tex]
[tex]\boxed{\boxed{v_1 = 331.1\:mL\:of\:isopropyl\:alcohol}}\Longleftarrow(solute\:volume)\:\:\:\:\:\:\bf\purple{\checkmark}[/tex]
Answer:
331.1 ml of isopropyl alcohol
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