Respuesta :
let
x---------> quantity (ton) of vegetables sold the first day
y---------> quantity (ton) of vegetables sold the second day
z---------> quantity (ton) of vegetables sold the third day
we know that
x=y-3---------> equation 1
z=(5/9)*(x+y)------> equation 2
x+y+z=98-----> equation 3
substitute equation 2 in equation 3
x+y+[(5/9)*(x+y)]=98----> multiply by 9----> 9x+9y+5x+5y=882
14x+14y=882-----> equation 4
to resolve the equations system formed by
x=y-3
14x+14y=882
using a graph tool
see the attached figure
the solution is
x=30
y=33
x+y+z=98----> z=98-(x+y)----> z=98-63---> 35
the answer is
vegetables sold the first day----> 30 ton
vegetables sold the second day----> 33 ton
vegetables sold the third day------> 35 ton
x---------> quantity (ton) of vegetables sold the first day
y---------> quantity (ton) of vegetables sold the second day
z---------> quantity (ton) of vegetables sold the third day
we know that
x=y-3---------> equation 1
z=(5/9)*(x+y)------> equation 2
x+y+z=98-----> equation 3
substitute equation 2 in equation 3
x+y+[(5/9)*(x+y)]=98----> multiply by 9----> 9x+9y+5x+5y=882
14x+14y=882-----> equation 4
to resolve the equations system formed by
x=y-3
14x+14y=882
using a graph tool
see the attached figure
the solution is
x=30
y=33
x+y+z=98----> z=98-(x+y)----> z=98-63---> 35
the answer is
vegetables sold the first day----> 30 ton
vegetables sold the second day----> 33 ton
vegetables sold the third day------> 35 ton

Answer:
amount sold on first day = 30 tons
amount sold on second day = 33 tons
amount sold in third day = 35 tons
Explanation:
Assume that the amount of vegetables sold on the second day is x.
We are given that:
Amount of vegetables sold on the first day is 3 tons less that sold on the second day.
This means that:
amount sold on first day = x - 3
Amount of vegetables sold on the third day is 5/9 the amount sold on the first two days.
This means that:
amount sold on third day = (5/9) (x + x - 3)
amount sold on third day = [tex] \frac{10}{9} x - \frac{5}{3} [/tex]
Now, we know that:
Total amount sold is 98 tons.
This means that:
98 = x - 3 + x + [tex] \frac{10}{9} x - \frac{5}{3} [/tex]
Now, we will solve for x as follows:
98 = [tex] \frac{28}{9} x - \frac{14}{3} [/tex]
882 = 28x - 42
882 + 42 = 28x
924 = 28x
x = 924/28
x = 33 tons
This means that:
amount sold on first day = x - 3 = 33 - 3 = 30 tons
amount sold on second day = x = 33 tons
amount sold on third day = [tex] \frac{10}{9} x - \frac{5}{3} [/tex] = [tex] \frac{10}{9} (33) - \frac{5}{3} [/tex] = 35 tons
Hope this helps :)
amount sold on first day = 30 tons
amount sold on second day = 33 tons
amount sold in third day = 35 tons
Explanation:
Assume that the amount of vegetables sold on the second day is x.
We are given that:
Amount of vegetables sold on the first day is 3 tons less that sold on the second day.
This means that:
amount sold on first day = x - 3
Amount of vegetables sold on the third day is 5/9 the amount sold on the first two days.
This means that:
amount sold on third day = (5/9) (x + x - 3)
amount sold on third day = [tex] \frac{10}{9} x - \frac{5}{3} [/tex]
Now, we know that:
Total amount sold is 98 tons.
This means that:
98 = x - 3 + x + [tex] \frac{10}{9} x - \frac{5}{3} [/tex]
Now, we will solve for x as follows:
98 = [tex] \frac{28}{9} x - \frac{14}{3} [/tex]
882 = 28x - 42
882 + 42 = 28x
924 = 28x
x = 924/28
x = 33 tons
This means that:
amount sold on first day = x - 3 = 33 - 3 = 30 tons
amount sold on second day = x = 33 tons
amount sold on third day = [tex] \frac{10}{9} x - \frac{5}{3} [/tex] = [tex] \frac{10}{9} (33) - \frac{5}{3} [/tex] = 35 tons
Hope this helps :)