To solve for the triangle we shall proceed as follows: B = 36°, a = 38, c = 17 using cosine rule: b^2=a^2+c^2-2accosB b^2=38^2+17^2-2*38*17cos36 b^2=697.7500 b=26.2
th missing angles will be evaluated using sine rule: a/sin A=b/sin B thus 38/sin A=26.2/sin 36 sin A=(38sin 36)/26.2 sin A=0.8525 A=58.49
since a is the longest side then A is the largest angle and it will be: A=180-58.49=121.51 also: c/sin C=b/sin B 17/sin C=26.2/sin 36 sin C=0.3814 C=22.42