Han found a way to compute complicated expressions more easily. Since 2 ⋅ 5 = 10 2⋅5=10, he looks for pairings of 2 2s and 5 5s that he knows equal 10 10. For example, 3 ⋅ 2 4 ⋅ 5 5 = 3 ⋅ 2 4 ⋅ 5 4 ⋅ 5 = ( 3 ⋅ 5 ) ⋅ ( 2 ⋅ 5 ) 4 = 15 ⋅ 1 0 4 = 150 , 000 3⋅2 4 ⋅5 5 =3⋅2 4 ⋅5 4 ⋅5=(3⋅5)⋅(2⋅5) 4 =15⋅10 4 =150,000 Use Han's technique to compute the following: a) 2 4 ⋅ 5 ⋅ ( 3 ⋅ 5 ) 3 2 4 ⋅5⋅(3⋅5) 3
