Calculate the molar solubility of CuS in a solution in which the [H₃O+] is held constant at 1.0 x 10⁻¹ M. Ka1(H2S) = 9.6 x 10⁻⁸, Ka2(HS-) = 1.3x10⁻¹⁴, Ksp(CuS) = 8.0 x 10⁻³⁷.
A) 1.78 × 10⁻¹⁸ mol/L
B) 2.65 × 10⁻²⁵ mol/L
C) 3.98 × 10⁻³³ mol/L
D) 5.60 × 10⁻⁴⁰ mol/L