tboling91552 tboling91552 13-03-2024 Mathematics contestada y(3)−2y′′+y′=7+5xeˣ; y(0)=y′(0)=0, y′′(0)=1. The solution is y(x)=a)7x+5xeˣ+x³ b)5x+7xeˣ+x³c)7+5xeˣ+x³d)7x+xeˣ+x³
